Combination of Capacitors

Determine the equivalent capacitance of capacitors in parallel combination.

Explain how to determine the equivalent capacitance of capacitors in series.

Find the equivalent capacitance of the combination of capacitors between the points $\mathrm{A}$ and $\mathrm{B}$. 

Find the equivalent capacitance between $\mathrm{AB}$$:$

Two capacitors $A$ and $B$ with capacities $3\mu F$ and $2\mu F$ are charged to a potential difference of $100 V$ and $180 V$ respectively. The plates of the capacitors are connected as shown in the figure with one wire of each capacitor free. The upper plate of $A$ is positive and that of $B$ is negative. An uncharged $2\mu F$ capacitor $C$ with lead wires falls on the free ends to complete the circuit. Calculate the final charge on the three capacitors and the amount of electrostatic energy stored in the system before and after completion of the circuit.

Explain Kirchoff's first law with capacitor.

In the given figure, find charge across each capacitor in steady state.

If two capacitors having capacitance of $5 \mu F$ and $10 \mu F$ respectively are connected in series across a $200 V$ supply, find the potential difference across each capacitor.

A part of circuit in a steady state along with the currents flowing in the branches, the values of resistances etc, is shown in the figure. Calculate the energy stored in the capacitor C $\left(4\mu F\right)$.

Calculate the steady state current in the $2 \Omega$ resistor shown in the circuit. The internal resistance of the battery is negligible and the capacitance of the condenser $C$ is $0.2 \mu F$.

Four plates of equal area$A$ are separated by equal distances $d$ and are arranged as shown in the figure. The equivalent capacity is

Three equal capacitors, each with capacitance $C$ are connected as shown in figure. Then the equivalent capacitance between point $A$ and $B$ is

For the figure shown equivalent capacitance between points $A$ and $B$ is